Solve
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| 5 people are standing in a line. How many different outcomes are possible? |
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Solve |
Step |
| This a permutation because order is important. It is the same type of problem as example 1. | |
| P(5, 5) = 5! = 5 × 4 × 3 × 2 × 1 = 120 | |
| Let's say we have 5 people A, B, C, D and E | |
| A, B, C, D, E | is one arrangement |
| B, A, C, D, E | another |
| C, B, A, D, E | and another... |
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There are 5 choices for the first spot. That leaves 4 choices left
for second spot. After the first 2 spots are chosen, there are 3
choices left for the 3rd spot and so on...
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