Solution for Problem 5.3.2

Find all possible rational roots and all rational roots of  P(x) = 4x3 - 15x2 - 31x + 30

Find all possible rational zeros - rational numbers are ratio of integers i.e. -2/1 = -2, 0, 1/2, -3/2

Solve

Step

p = ± 1, ± 2,  ± 3,  ± 5,  ± 6, ± 10, ± 15, ± 30

q ± 1, ± 2, ± 4

p/q where p are factors of the last coefficient 30.  q are the factors of the first coefficient 4.

Recall p/1 = p

where q = 2 get rid of repeats

where q = 4 get rid of repeats
All possible rational zeros - Final list-  whooa!!
  ± 1, ± 2,  ± 3,  ± 5,  ± 6, ± 10, ± 15, ± 30 and 

Try the easy ones first.

Start with -2 (I tried others first but they failed - You can use Descartes' Rules of Signs to narrow the search.)

  

 Q(x) = 4x2 - 23x + 15 =  0
(4x
- 3)(x - 5) = 0

x = 3/4   or x = 5

There are three zeros for P(x) are{ -2, 3/4, 5}

Side note:  P(x) = 4x3 - 15x2 - 31x + 30 = (x + 2)(4x - 3)(x - 5)