Solution for Problem 2.4.3

Given:  x2y2 - 5x + 4y  - 2 = 0
Put in
the Standard Equation form.   (x - h)2 + (y - k)2 = r2 

x2y2 - 5x + 4y - 2 = 0

Group like terms

x2 - 5x + y2  + 4y  = 2

Add 2 to both sides

x2 - 5x + (5/2)2 + y2 + 4y  + 22 = 2 + (5/2)2 + 22 *

Take half the middle term and square it. Note half of 3 is 3/2

(x - 5/2)2 + (x + 2)2  =  2 + 25/4 + 4

Complete the squares!!
Add those fractions...

(x - 5/2)2 + (x + 2)2   = 49/4

Standard Equation form

(x - h)2 + (y - k)2 = r2 

The center is (5/2, -2)  Radius is 

*Click here for completing the square help with this step.