Given: x2
+ y2
- 5x
+ 4y -
2 = 0
Put in
the Standard Equation
form. (x - h)2 + (y
- k)2 = r2
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x2 + y2 - 5x + 4y - 2 = 0 |
Group like terms |
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x2 - 5x + y2 + 4y = 2 |
Add 2 to both sides |
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x2 - 5x + (5/2)2 + y2 + 4y + 22 = 2 + (5/2)2 + 22 * |
Take half the middle term and square it. Note half of 3 is 3/2 |
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(x - 5/2)2 + (x + 2)2 = 2 + 25/4 + 4 |
Complete the
squares!! Add those fractions... |
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(x - 5/2)2 + (x + 2)2 = 49/4 |
Standard Equation form |
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(x - h)2 + (y - k)2 = r2 |
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The center is (5/2, -2) Radius is |
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*Click here for completing the square help with this step. |
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